Are you new to SQL and preparing for your first job that requires SQL knowledge?
This blog post is designed specifically for beginners like you who are just starting out on their journey with SQL. Whether you're a student, a recent graduate, or someone looking to transition into a tech role, this guide will help you build a strong foundation in SQL concepts, understand common SQL queries, and prepare you for the types of SQL tasks you might encounter in your first job. We'll break down complex concepts into easy-to-understand steps, provide practical examples, and give you tips to succeed in interviews and on the job. Let's get you job-ready with SQL!
Below is the table structure for the `customer`, `user_account`, and `contact` tables in a more visual format:
Here are two slightly more complex SQL query questions along with their detailed explanations:
Question 1: Find the Top 3 Customers by Total Purchase Amount
You have a `customer` table and an `invoice` table. The `invoice` table contains information about customer purchases, including the `customer_id`, `total_amount`, and `invoice_date`. Your task is to find the top 3 customers who have spent the most, along with their total amount spent and the number of purchases they made. Order the result by total amount spent in descending order.
Tables:
- customer: Contains customer information.
- `id`: INT (Primary Key)
- `customer_name`: VARCHAR(255)
- invoice: Contains invoice information.
- `customer_id`: INT (Foreign Key referencing `customer.id`)
- `total_amount`: DECIMAL(10,2)
- `invoice_date`: DATE
Query:
```sql
SELECT
c.id AS customer_id,
c.customer_name,
SUM(i.total_amount) AS total_spent,
COUNT(i.id) AS total_purchases
FROM
customer c
JOIN
invoice i ON c.id = i.customer_id
GROUP BY
c.id, c.customer_name
ORDER BY
total_spent DESC
LIMIT 3;
```
Explanation:
- JOIN: Combines the `customer` and `invoice` tables based on the `customer_id`.
- SUM(i.total_amount): Calculates the total amount each customer has spent.
- COUNT(i.id): Counts the number of invoices (purchases) for each customer.
- GROUP BY c.id, c.customer_name: Groups the results by customer.
- ORDER BY total_spent DESC: Orders the results by the total amount spent in descending order.
- LIMIT 3: Limits the result to the top 3 customers.
---
Question 2: Find All Users Who Have Never Made a Purchase
You have a `user_account` table and an `order` table. Some users might have registered but never made a purchase. Your task is to find all users who have never placed an order, displaying their user ID, first name, last name, and email.
Tables:
- user_account: Contains user information.
- `id`: INT (Primary Key)
- `first_name`: VARCHAR(64)
- `last_name`: VARCHAR(64)
- `email`: VARCHAR(128)
- order: Contains order information.
- `user_id`: INT (Foreign Key referencing `user_account.id`)
- `order_date`: DATE
Query:
```sql
SELECT
ua.id AS user_id,
ua.first_name,
ua.last_name,
ua.email
FROM
user_account ua
LEFT JOIN
order o ON ua.id = o.user_id
WHERE
o.user_id IS NULL;
```
Explanation:
- LEFT JOIN: Joins the `user_account` table with the `order` table to include all users, even if they haven't placed an order.
- WHERE o.user_id IS NULL: Filters out only those users who have never made an order (i.e., no matching record in the `order` table).
- ua.id, ua.first_name, ua.last_name, ua.email: Selects the relevant user information for the result.
You can practice SQL without installing a database server by using online SQL platforms like:
1. SQLFiddle (www.sqlfiddle.com): Allows you to write and execute SQL queries in an interactive online environment.
2. DB Fiddle (www.db-fiddle.com): Similar to SQLFiddle, supporting multiple database systems for practice.
3. LeetCode (www.leetcode.com): Offers SQL challenges to solve directly in your browser.
4. HackerRank (www.hackerrank.com/domains/sql): Provides SQL problems with an in-browser SQL editor for practice.
5. Mode Analytics SQL Tutorial (www.mode.com/sql-tutorial/): Offers an interactive SQL tutorial where you can write and test queries.
These tools allow you to practice SQL queries without needing to install anything on your local machine.